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Table I.

DRB1-DQA1-DQB1 haplotype frequencies in all patients with Lyme arthritis and in European-American control subjects or Lyme arthritis patients stratified by antibiotic response

DRB1-DQA1-DQB1Haplotype frequencies
G valueHaplotype frequencies
G value
European-American
 subjectsaAll Lyme arthritis
 patientsbLyme arthritis patients




Antibiotic
 refractoryc
Antibiotic
 responsived

 % %  % %  
0101-0101-0501 9.1 7.9 0.4 10.6 3.5 
0102-0101-0501 1.4 1.7 0.1    
0103-0101-0501 0.5 2.1 6.7 0.7 3.1 
0301-0501-0201 13.1 12.0 0.2 10.6 14 0.6 
0401-03-0301 5.4 6.6 0.6 7.7 0.7 
0401-03-0302 4.9 3.3 1.3 4.9 3.2 
0402-03-0302 1.0 1.7 0.9    
0403-03-0302 0.4 1.9    
0404-03-0302 3.9 5.0 0.6 5.0 0.0 
0405-03-0302 0.3 0.8 1.5    
0407-03-0301 0.9 1.2 0.3    
0701-0201-0202 11.1 9.5 0.5 11.3 1.2 
0701-0201-0303 3.7 1.2 5.0    
0801-0401-0402 2.2 2.9 0.4 0.7 5.9 
0901-03-0303 0.8 0.4 0.5    
1001-0104-0503 0.7 0.0 3.3    
1101-0501-0301 5.6 5.4 2.8 4.1 
1103-0501-0301 0.3 0.4    
1104-0501-0301 2.7 3.3 0.3 0.7 7.4 
1201-0501-0301 1.1 2.5 2.9 2.8 0.2 
1301-0103-0603 5.6 3.7 1.6 3.5 0.0 
1302-0102-0604 3.4 2.5 0.6 2.1 0.2 
1302-0102-0609 0.7 1.2 0.7    
1303-0501-0301 0.7 2.5 5.6 2.1 0.2 
1305-0501-0301 0.3 0.4 0.2    
1401-0104-0503 2.0 1.7 0.1    
1501-0102-0602 14.2 10.7 2.1 12.0 0.5 
1501-0102-0603 2.1 0.8 2.2    
1502-0103-0601 0.7 0.8 0.1    
1601-0102-0502 1.0 2.1 2.2 2.1 0.0 
Combinede 1.3 3.7  12.0 20.0  
Total 100.0 100.0 42.8 100.0 100.0 30.8 
P value   0.05   0.009f 
Degree of freedom   29   15 
Wn effect size statistic   0.13   0.35 
DRB1-DQA1-DQB1Haplotype frequencies
G valueHaplotype frequencies
G value
European-American
 subjectsaAll Lyme arthritis
 patientsbLyme arthritis patients




Antibiotic
 refractoryc
Antibiotic
 responsived

 % %  % %  
0101-0101-0501 9.1 7.9 0.4 10.6 3.5 
0102-0101-0501 1.4 1.7 0.1    
0103-0101-0501 0.5 2.1 6.7 0.7 3.1 
0301-0501-0201 13.1 12.0 0.2 10.6 14 0.6 
0401-03-0301 5.4 6.6 0.6 7.7 0.7 
0401-03-0302 4.9 3.3 1.3 4.9 3.2 
0402-03-0302 1.0 1.7 0.9    
0403-03-0302 0.4 1.9    
0404-03-0302 3.9 5.0 0.6 5.0 0.0 
0405-03-0302 0.3 0.8 1.5    
0407-03-0301 0.9 1.2 0.3    
0701-0201-0202 11.1 9.5 0.5 11.3 1.2 
0701-0201-0303 3.7 1.2 5.0    
0801-0401-0402 2.2 2.9 0.4 0.7 5.9 
0901-03-0303 0.8 0.4 0.5    
1001-0104-0503 0.7 0.0 3.3    
1101-0501-0301 5.6 5.4 2.8 4.1 
1103-0501-0301 0.3 0.4    
1104-0501-0301 2.7 3.3 0.3 0.7 7.4 
1201-0501-0301 1.1 2.5 2.9 2.8 0.2 
1301-0103-0603 5.6 3.7 1.6 3.5 0.0 
1302-0102-0604 3.4 2.5 0.6 2.1 0.2 
1302-0102-0609 0.7 1.2 0.7    
1303-0501-0301 0.7 2.5 5.6 2.1 0.2 
1305-0501-0301 0.3 0.4 0.2    
1401-0104-0503 2.0 1.7 0.1    
1501-0102-0602 14.2 10.7 2.1 12.0 0.5 
1501-0102-0603 2.1 0.8 2.2    
1502-0103-0601 0.7 0.8 0.1    
1601-0102-0502 1.0 2.1 2.2 2.1 0.0 
Combinede 1.3 3.7  12.0 20.0  
Total 100.0 100.0 42.8 100.0 100.0 30.8 
P value   0.05   0.009f 
Degree of freedom   29   15 
Wn effect size statistic   0.13   0.35 

The 42 rare haplotypes that were found only in the control population are not shown here, but a complete listing of haplotypes in the control population has been published previously (19). Of the 13 rare haplotypes in patients with Lyme arthritis, 12 (0101-0102-0504, 0403-03-0304, 0408-03-0301, 0409-03-0301, 0416-03-0302, 1102-0501-0301, 1104-0101-0301, 1104-0103-0603, 1301-0103-0614, 1302-0102-0501, 1401-0104-0502, and 1501-0102-0502) were each found in only one patient, and one (0404-03-0402) was found in two patients. For comparison of the groups, 1.3% of the haplotypes in normal control subjects and 3.7% of those in all Lyme arthritis patients were excluded from analysis. For the analysis of patients by antibiotic response, 12% of those in the refractory group and 20% of those in the responsive group were excluded.

a

n = 3,798.

b

n = 242.

c

n = 142.

d

n = 100.

e

When ≤5 individuals with Lyme arthritis or ≤10 individuals in the control population had a given haplotype, the values were excluded from analysis (empty cells).

f

For log likelihood statistic verification, the 2 × 15 table was also calculated by an exact test; P = 0.01.

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